A wire is 1.1 m long and has a mass of 0.023 kg. The wire is stretched between t

Question

A wire is 1.1 m long and has a mass of 0.023 kg. The wire is stretched between two points and when driven by an oscillator at 520 Hz you notice that the wire is oscillating with four antinodes (four loops) between the rigid supports What is the fundamental frequency of the wire? Hz What is the fundamental wavelength of the wire? m What is the velocity of the wave in the wire? m/s What is the tension in the wire? N What is the next lowest frequency (closest to, but lower than 520 Hz) that will produce a standing wave on the wire? Hz How many antinodes does this standing wave have?

Explanation / Answer

a)

f = 520/4 = 130 Hz

b)

= 2L = 2 * 1 = 2 m

c)

v = f = 2 * 130 = 260 m/s

d)

T = m/L v2 = (0.021/1)*(260*260) = 1420 N

e)

f' = 2f = 2 * 130 = 260 Hz

f)

3

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