A wire 28.0 cm long lies along the z-axis and carries a current of 8.20 A in the

Question

A wire 28.0 cm long lies along the z-axis and carries a current of 8.20 A in the +z-direction. The magnetic field is uniform and has components Bx = -0.238 T , By = -0.989 T , and Bz = -0.349 T .

Part A Find the x-component of the magnetic force on the wire. F_x=......N

Part B Find the y-component of the magnetic force on the wire.

Part C Find the z-component of the magnetic force on the wire.

Part D What is the magnitude of the net magnetic force on the wire? F=......N

Your help is hugely appreciated.

Explanation / Answer

let i,j and k are unit vectors along +ve x, +ve y and +ve z axis.

force on a current carrying wire=I*cross product of L and B

where I=current magnitude

L=length of the wire

direction of L is along the direction of current

B is magnetic field

given I=8.2 A

L=28 cm=0.28 m

direction of current is along +k.

B=-0.238 i -0.989 j -0.349 k

magnetic force=8.2*0.28*cross product of (k and (-0.238 i -0.989 j -0.349 k))

=8.2*0.28*(-0.238 j +0.989 i)

=2.27074 i -0.54645 j

answers are:

part a:
x component of magnetic force=2.27074 N

part b:

y component of magnetic force=-0.54645 N

part c:

z component of magnetic force=0 N

part d:

magnitude of force

=sqrt(2.27074^2+0.54645^2)

=2.3356 N

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