A wire 4.00 m long and 6.00 mm in diameter has a resistance of15.0 m. A potentia

Question

A wire 4.00 m long and 6.00 mm in diameter has a resistance of15.0 m. A potential difference of 23.0 V is applied betweenthe ends. (a) What is the current in the wire? (b) What is themagnitude of the current density? (c) Calculate the resistivity ofthe wire material. A wire 4.00 m long and 6.00 mm in diameter has a resistance of15.0 m. A potential difference of 23.0 V is applied betweenthe ends. (a) What is the current in the wire? (b) What is themagnitude of the current density? (c) Calculate the resistivity ofthe wire material.
A wire 4.00 m long and 6.00 mm in diameter has a resistance of15.0 m. A potential difference of 23.0 V is applied betweenthe ends. (a) What is the current in the wire? (b) What is themagnitude of the current density? (c) Calculate the resistivity ofthe wire material.

Explanation / Answer

Given that The length of the wire (L) = 4.00m The diameter of the wire (d) = 6.00mm Then the radius of the wire (r) =3.00mm                                              =0.003m Area of the wire (A) = r2                                 =(3.14)(0.003m)2                                =0.00002826m2                                =0.00002826m2 Resistance of the wire is (R) =15.0m                                           =0.015 A potential difference of (V) = 23.0 V is appliedbetween the ends a) The current in the wire is (I) = V/R b) The current density (J) = I/A c) The resistivity of the material of the wire is given by                            R =L/A                              =RA/ now substitute all the above values you get the requiredanswer

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