A wire 3.400 m long and 4.000 mm in diameterhas a resistance of 4.5725 m . A pot

Question

A wire 3.400 m long and 4.000 mm in diameterhas a resistance of 4.5725 m. A potential differenceof 29.000 V is applied between the ends. What is thecurrent in the wire? (B)What is the current density? (C)Calculate the conductivity of the wirematerial.(S/m) (D) Identifyt eh material I have A and D, having problems calculating B and C. A wire 3.400 m long and 4.000 mm in diameterhas a resistance of 4.5725 m. A potential differenceof 29.000 V is applied between the ends. What is thecurrent in the wire? (B)What is the current density? (C)Calculate the conductivity of the wirematerial.(S/m) (D) Identifyt eh material I have A and D, having problems calculating B and C. (D) Identifyt eh material I have A and D, having problems calculating B and C.

Explanation / Answer

   B.   Currentdensity   j   =   i /A   =   (V/R) /A   =   29.000 / 4.5725 *10-3 * ( * (4.00 *10-3)2             j      =   1.2624* 108   A/m2    C.   Conductivity      =   1/         and resistivity      =   R* A / l       =>      =   l/ R * A   =   3.400 / 4.5725 *10-3 * ( * (4.00 *10-3)2   =   1.48* 108   S/m

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