The moment of inertia of a (non-uniform) disk about its mass centre is I = 0.025

Question

The moment of inertia of a (non-uniform) disk about its mass centre is I = 0.025.kg.m2. The stationary disk is subjected to a constant 10 N.m torque.

a) What is the magnitude of the resulting angular acceleration of the disk?

b)If the disk has a radius of = 0.25 m, and is accelerated from rest, how long before the disk has completed one revolution and what is the magnitude of the linear acceleration of a point on the perimeter when one revolution has been completed?

c)Using the disk described in a & b, use the work –energy principle to determine the angular velocity of the disk after it has completed one revolution.

Explanation / Answer

solution

M = I

= M / I

= 10 / 0.025

= 400 rad/s2

at = r

= 400 X 0.25

= 100 m/s2

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