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The molarity of water is calculated to be approximately 55.5 M at room temperatu

ID: 823491 • Letter: T

Question

The molarity of water is calculated to be approximately 55.5 M at room temperature. Question 16 options: True False


The conjugate acid of I- is: HI I2- H+ H2I HIO3

An amphoteric substance can act as both a weak base and a weak acid. Question 2 options: True False
The molarity of water is calculated to be approximately 55.5 M at room temperature. Question 16 options: True False
The molarity of water is calculated to be approximately 55.5 M at room temperature. Question 16 options: True False
The molarity of water is calculated to be approximately 55.5 M at room temperature. Question 16 options: True False The molarity of water is calculated to be approximately 55.5 M at room temperature. The molarity of water is calculated to be approximately 55.5 M at room temperature. True False




The conjugate acid of I- is: The conjugate acid of I- is: HI HI I2- I2- H+ H+ H2I H2I HIO3 HIO3



An amphoteric substance can act as both a weak base and a weak acid. Question 2 options: True False
An amphoteric substance can act as both a weak base and a weak acid. Question 2 options: True False
An amphoteric substance can act as both a weak base and a weak acid. Question 2 options: True False An amphoteric substance can act as both a weak base and a weak acid. An amphoteric substance can act as both a weak base and a weak acid. True False
True False

Explanation / Answer

1). true....

Molarity is defined as the number of moles of the solute per liter of solution

Molarity = Number of moles of solute/Volume of solution (in litres)

we are given that density of water is 1g/mL. This is equal to 1Kg/L. Therefore mass of 1L of water will be = density of water x volume (using the relation density = mass/volume)

= 1Kg/L x 1L...

= 1Kg = 1000g

Therefore, number of moles in 1Kg of water = mass/molar mass = 1000/18 = 55.56

Therefore molarity of water = 55.56/1 Liter = 55.56moles/L....

2).HI

HI(aq) + H2O(l) ----> I-(aq0 + H3O+(aq)

when the forward reaction occurs, HI donates a proton to water (so it acts as the base) to form hydronium. When the reverse reaction occurs, the hydronium ion acts as the acid, donating a proton to the I-. Together, HI and I- are said to be conjugate acid-base pairs. Conjugate acid-basse pairs are compounds that differ by the presence of one proton, or H+. All acids have a conjugate base, which is formed when their proton has been donated; likewise, all bases have a conjugate acid, formed after they have accepted a proton.


3). true....

Amphoteric substance is the one that can react as either an acid or base. "Partly one and partly the other; neither acid nor alkaline, neutral"

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