A free-body diagram of a 1.00kg block pulled across a surface by a string. The s

Question

A free-body diagram of a 1.00kg block pulled across a surface by a string. The string's tension is T=5N. The string makes and angle of 37 degrees with the horizontal. The coefficient of the kinetic friction is uk=0.30 B) determine the x-component of the force of friction. A free-body diagram of a 1.00kg block pulled across a surface by a string. The string's tension is T=5N. The string makes and angle of 37 degrees with the horizontal. The coefficient of the kinetic friction is uk=0.30 B) determine the x-component of the force of friction. B) determine the x-component of the force of friction.

Explanation / Answer

The block is not moving vertically so the net force vertically is zero.

Tsin37 + R = mg

=> 0.6018 T + R = 1(9.8)

=> R = 6.791 N

so, x component of the force of friction = Fr = ukR = 0.3(6.791) = 2.3073 N.

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