A block of weight w = 40.0N sits on a frictionless inclined plane, which makes a

Question

A block of weight w = 40.0N sits on a frictionless inclined plane, which makes an angle = 24.0 with respect to the horizontal, as shown in the figure. (Figure 1) A force of magnitude F = 16.3N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed.

Part A

The block moves up an incline with constant speed. What is the total work Wtotal done on the block by all forces as the block moves a distance L = 4.40m up the incline? Include only the work done after the block has started moving at constant speed, not the work needed to start the block moving from rest.

Part B

What is Wg, the work done on the block by the force of gravity w?  as the block moves a distance L = 4.40m up the incline?

Part C

What is WF, the work done on the block by the applied force F?  as the block moves a distance L = 4.40m up the incline?

Part D

What is WN, the work done on the block by the normal force as the block moves a distance L = 4.40mup the inclined plane?

Explanation / Answer

h = L*sin24 = 1.79 m

partA)

Wtot = -m*g*sin24*L = 40*sin24*4.4 = 71.6 J

part B) Wg = -m*g*h = -71.6 J

partC) Wf = F*L*cos0 = 71.72 J

D) WN = Fn*L*cos90 = 0

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