A block of moss 5.00 kg is pushed across a rough horizontal surface from point A

Question

A block of moss 5.00 kg is pushed across a rough horizontal surface from point A to point B by a force of magnitude P = 40.0 N at an angle 30.0 degree below the horizontal, as shown in the figure. There is no friction between the block and the floor, the points A and B are 8.00 m apart. i. How much work is done on the block by the force P between A and B? ii. If the speed of the block was already 3.00 m/s to the right when the block was at point 'A'. what will be its kinetic energy when it Is at point 'B'?

Explanation / Answer

M=5kg F=40N s=8m

Fcos30 wil do the work done so

W=40 ×cos30×8=277.13J

Acc to work energy ttheorm

Work done = change in K.E.

277.13=1/2mv^2-1/2mu^2

1/2mv^2= 299.63

V=10.9m/s

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