For the reaction A+B+CD+E, the initial reaction rate was measured for various in

Question

For the reaction A+B+CD+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected:

Part A

What is the reaction order with respect to A?

Express your answer as an integer.

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Part B

What is the reaction order with respect to B?

Express your answer as an integer.

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Part C

What is the reaction order with respect to C?

Express your answer as an integer.

Trial [A]
(mol L1) [B]
(mol L1) [C]
(mol L1) Initial rate
(mol L1 s1) 1 0.50 0.50 0.50 1.5×104 2 0.50 0.50 1.50 4.5×104 3 1.00 0.50 0.50 6.0×104 4 1.00 1.00 0.50 6.0×104

Explanation / Answer

Part A

What is the reaction order with respect to A?

We write rate law

Rate = k [ A]l [B]m [C]n

l , m and n are the orders with respect to A, B and C respectively. We select two exp so that concentration of two of three are constant in that.

And then we take a ratio of rate law for both selected experiment.

Lets select exp 1 and exp 3 , k is constant for all exp. (same reaction)

Rate 3 / rate 1 = [ A]3l [B]3m [C]3n /   [ A]1l [B]1m [C]1n

6.0×104 / 1.5×104   = ( 1.00 / 0.50 )l

4 = 2l

Lets take ln of both side

Ln 4 = l ln 2

l = 2

Order with respect to A is 2

Part B

What is the reaction order with respect to B?

For B we select exp 4 and exp 3

Rate 3 / rate 4 = [ A]3l [B]3m [C]3n /   [ A]4l [B]4m [C]4n

6.0E-4 / 6.0E-4 = (0.50/1.0 )m

ln 1 = m ln ( 0.5)

m = 0

Order with respect to B = 0

Part C

What is the reaction order with respect to C?

Exp 2 and exp 1

Rate 2 / rate 1 = [ A]2l [B]2m [C]2n /   [ A]1l [B]1m [C]1n

4.5 E-4 / 1.5 E -4 = ( 1.50/0.50)n

ln 3 = n ln 3

n = 1

Order with respect to C = 1

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