For the reaction 2 so_2(g) + o_2(g) 2 so_3 if initially P(SO_2) = 1.2 atm, P(O_2

Question

For the reaction 2 so_2(g) + o_2(g) 2 so_3 if initially P(SO_2) = 1.2 atm, P(O_2) = 1.8 atm, and P(SO_3)= 2.1 aim. calculate deltaG for this reaction at 25 C. The following data valid at 25degreeC: Which way will the reaction proceed to reach equilibrium? Calculate the equilibrium pressure of C0_2 due to the decomposition of mgco_3 at 25degreec the information below. Consider the gas phase reaction between A_2 and B_2 to form 2 AB at 298 K What is the value of deltaG? Which way will the reaction proceed to reach equilibrium? What is favored at equilibrium? Products or reactants

Explanation / Answer

The answer is: 3. C) 138.7 kJ/mol


2 SO2 + O2 <=> 2 SO3

DGo = DGf(products) - DGf(reactants)

= 2 x DGf(SO3) - 2 x DGf(SO2) - DGf(O2)

= 2 x (-370.4) - 2 x (-300.4) - 0 = -140 kJ/mol


Reaction quotient Q = P(SO3)^2/P(SO2)^2.P(O2)

= 2.1^2/(1.2^2 x 1.8) = 1.7014


Molar gas constant R = 8.314 x 10^(-3) kJ/mol.K

Temperature T = 25 deg C = 298.15 K


DG = DGo + RT ln Q

= -140 + 8.314 x 10^(-3) x 298.15 x ln(1.7014)

= -138.7 kJ/mol

Dg for the reaction is negative so it is spotaneous reaction.

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.