A mass spectrometer similar to the one in the figure below is designed to separa

Question

A mass spectrometer similar to the one in the figure below is designed to separate protein fragments. The fragments are ionized by removinga single electron and then enter a 0.90 T uniform magnetic field at a speed of 2.9 × 105 m/s. If a fragment has a mass 70 times the mass of the proton, what will be the distance between the points where the ion enters and exits the magnetic field? and aceleated o maws follow pah of a particalar velocity of differest are selected to enter n Ouly ioas of a panicular mass reach the exit slit aad continse to the detecto

Explanation / Answer

KE = PE

0.5 mv^2 = eV

or v = sqrt(2eV/m)

apply centripetal force = magnetic force

i.e mv^2/r = qvB,

where m = mass o the charged particle

v = velocity,   r = radius ,

q = charge = 1.6*10^-19 C

B = magnetic field

so now , r = mv/qB

Put values

r=70*1.67e-27 * 2.9e5 /(1.6e-19 * 0.90)

r = 0.235 m

so total disatnce = diameter = 2r = 2*0.235=0.47 m  

= 47 cm

I hope help you.....

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