The reaction S2O82-(aq) + 3 I-(aq) 2 SO42-(aq) + I3-(aq) was studied at a certai

Question

The reaction S2O82-(aq) + 3 I-(aq) 2 SO42-(aq) + I3-(aq) was studied at a certain temperature with the following results:

Experiment [S2O82-(aq)] (M) [I-(aq)] (M) Rate (M/s)
1 0.0288 0.0288 4.01e-06
2 0.0288 0.0576 8.03e-06
3 0.0576 0.0288 8.03e-06
4 0.0576 0.0576 1.61e-05



(a) What is the rate law for this reaction?

Rate = k [S2O82-(aq)] [I-(aq)]
Rate = k [S2O82-(aq)]2 [I-(aq)]
Rate = k [S2O82-(aq)] [I-(aq)]2
Rate = k [S2O82-(aq)]2 [I-(aq)]2
Rate = k [S2O82-(aq)] [I-(aq)]3
Rate = k [S2O82-(aq)]4 [I-(aq)]






(b) What is the value of the rate constant?







(c) What is the reaction rate when the concentration of S2O82-(aq) is 0.0564 M and that of I-(aq) is 0.0671 M if the temperature is the same as that used to obtain the data shown above?



M/s

Explanation / Answer

k[S2O8-2][I-]

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