The reaction 2NO(g)+ 2H2(g) ---> N2(g)+ 2H2O(g) was studied at 904 °C, and the d
ID: 542558 • Letter: T
Question
The reaction 2NO(g)+ 2H2(g) ---> N2(g)+ 2H2O(g)
was studied at 904 °C, and the data in the table were collected.
Reaction Concentration (mol/L)
Rate of Appearance of N2
[NO]
[H2]
0.498
0.122
0.191
0.249
0.122
0.0478
0.249
0.244
0.0956
0.125
0.488
0.0482
A) Determine the order of the reaction for each reactant.
reaction order in [NO] = ____
reaction order in [H2] = ____
B) Write the rate equation for the reaction.
(Use k for the rate constant.)
Rate = ____
C) What is the rate constant for the reaction?
Rate constant = _____ L2/mol2·s
D) Find the rate of appearance of at the instant when = 0.330 mol/L and = 0.325 mol/L.
Rate = _____ mol/L·s
Reaction Concentration (mol/L)
Rate of Appearance of N2
[NO]
[H2]
(mol/L·s)0.498
0.122
0.191
0.249
0.122
0.0478
0.249
0.244
0.0956
0.125
0.488
0.0482
Explanation / Answer
A)
see experiment 2 and 1:
[NO] doubles
[H2] is constant
rate becomes 4 times
so, order of NO is 2
see experiment 2 and 3:
[NO] is constant
[H2] doubles
rate doubles
so, order of H2 is 1
B)
Rate law is:
rate = k*[NO]^2*[H2]
C)
Put values from 1st row of table in rate law
rate = k*[NO]^2*[H2]
0.191 = k*0.498^2*0.122^1
k = 6.313 M-2.s-1
k = 6.313 L2/mol2.s
Answer: 6.313 L2/mol2.s
D)
rate = k*[NO]^2*[H2]
rate =6.313*0.330^2*0.325^1
rate = 0.223 M/s
rate = 0.223 mol/L.s
Answer: 0.223 mol/L.s
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