The reaction 2ClO2(aq)+2OH^-(aq)------>ClO3^- (aq)+ClO2^- (aq)+H2O(l) was studie
ID: 840822 • Letter: T
Question
The reaction 2ClO2(aq)+2OH^-(aq)------>ClO3^- (aq)+ClO2^- (aq)+H2O(l) was studied with the following results: Experiment [ClO2](M) [OH^-](M) Rate (M/s) 1 0.060 0.030 0.0248 2 0.020 0.030 0.00276 3 0.020 0.090 0.00828
Part A
Determine the rate law for the reaction. which of the following
Part B
Calculate the rate constant with proper units.
Express your answer using two significant figures.
Part C
Calculate the rate when [ClO2]= 0.150M and [OH?]= 4.0
1. rate=k[ClO2]2[OH?] 2. rate=k[ClO2]2[OH?]2 3. rate=k[ClO2][OH?]2 4. rate=k[OH?]Explanation / Answer
let the order of the reaction be x when compared to OH-
so,
0.00828/0.00276=3^x
or x=1
let the reaction be of ordey y with respect to ClO-
so,
0.0248/0.00276=(0.06/0.02)^y
or y=2
so the answer is rate=k[ClO2]2[OH?]
b) 0.0248 = k*0.06^2*0.03
or k=229.63
c)rate = 229.63*0.15^2*4*10^-2
=0.20667 M/s
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