Dogs with black fur require E_B_ for their coat color, B giving the the black an

Question

Dogs with black fur require E_B_ for their coat color, B giving the the black and E allowing for a number of pigments. The labs are in hardy-Weinberg population which has an E allele with the frequency of .821and the ab allele has a frequency of .698 what will be the proportion of black dogs? Dogs with black fur require E_B_ for their coat color, B giving the the black and E allowing for a number of pigments. The labs are in hardy-Weinberg population which has an E allele with the frequency of .821and the ab allele has a frequency of .698 what will be the proportion of black dogs?

Explanation / Answer

Dogs with black fur with pigment = EeBb

EeBb x EeBb

            Ee    Bb

Ee     EeEe     EeBb

Bb     EeBb       BbBb

Genotypes = 1EeEe, 2 EeBb, 1 BbBb

proportion of black dogs : 1-0.698 = 0.302

0.698 -0.302 =0.396 = P( BbBb) +P( EeBb) +P (EeEe) =1

                                    = 0.698 + 0.396 + 0.302 =1

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.