Ammonium bisulfide, NH4HS, forms ammonia, NH3, and hydrogen sulfide, H2S, throug

Question

Ammonium bisulfide, NH4HS, forms ammonia, NH3, and hydrogen sulfide, H2S, through the reaction NH4HS(s)NH3(g)+H2S(g) This reaction has a Kp value of 0.120 at 25 C. The Initial pressure of H2S(g) is flask is 6.46 x 10^-2 atm.

In addition to the H2S already present in the flask, solid NH4HS is added until there is excess unreacted solid remaining.

a) What are the partial pressures of NH3 and H2S at equilibrium, that is, what are the values of PNH3and PH2S, respectively?

Enter the partial pressure of ammonia followed by the partial pressure of hydrogen sulfide numerically in atmospheres separated by a comma.

pNH3, pH2S = ______________________atm

b) What is the mole fraction, , of H2S in the gas mixture at equilibrium?

Express your answer numerically.

xH2S = ______________

c)What is the minimum mass of NH4HS that must be added to the 5.00-L flask when charged with the 0.450 g of pure H2S(g), at 25 C to achieve equilibrium?

Express your answer numerically in grams.

mass> ____________________

Explanation / Answer

                  NH4HS(s)NH3(g)+H2S(g)

          I                                          0.0646

          C              0                  +x         +x

          E             0                     +x       0.0646+x

           Kp = PH2S PNH3

         0.12   = (0.0646+x)(x)

         x = 0.315

   PH2S   = 0.0646 + 0.315 = 0.3796atm

   PNH3   = x =                      = 0.315M

mole fraction of H2S = PH2s/total pressure

                                  = 0.3796/0.315+0.3796

                                   = 0.3796/0.6946 = 0.546

     P

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