Ammonia gas is synthesized according to the balanced equation below. N_2(g) + 3

Question

Ammonia gas is synthesized according to the balanced equation below. N_2(g) + 3 H_2(g) rightarrow 2 NH_3 (g) If 2.50 L N_2 react with 7.00 L H_2, what is the theoretical yield (in liters) of NH_3? Assume that the volumes of reactants and products are measured at the same temperature and pressure. 2.50 L 4.67 L 5.00 L 7.00 L 10.5 L An unknown gaseous hydrocarbon contains 85.63 % C. Its density equals 0.488 g/L at 0.355 atm and 373 K. What is the molecular formula of the gas? (R = 0.08206 L middot atm/mol middot K) You must SHOW EF to MF calculation to receive FULL CREDIT C_2 H_4 C_3 H_6 C_4 H_8 C_5 H_10 C_6 H_12 Carbon dioxide gas diffuses through a barrier at a rate of 0.40 mL/minute. If an unknown gas diffuses through the same barrier at a rate of 0.31 mL/minute, what is the molar mass of the gas? 26 g/mol 28 g/mol 51 g/mol 57 g/mol 73 g/mol

Explanation / Answer

7)volume is directly proportional to number of moles.

vN2:vNH3=1:2

Therefore volume of NH3=(2.5x2)L =5.0L

8)pv=nRT

n/v=p/RT

n/v=0.355atm/0.08206l atm/mol K x373K

n/v=0.0116 mol L-1----------(1)

d=m/v

n=dv/M

n/v=d/M

0.0116 mol L-1=0.488gL-1/M

M=42.07g/mol

14*n=42.07

n=3

answer is 3(CH2)=C3H6

using eq.(1)

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