Ammonia gas reacts with hydrogen chloride according to the reaction given below,

Question

Ammonia gas reacts with hydrogen chloride according to the reaction given below, which must also be balanced. if 7.00g of NH3 is reacted with 12.0g of HCl in a 1.00L container at 25C, what will the final pressure, in atmospheres, be in the reaction container? (the product is a solid, it has NO vapor pressure) __NH3 (g) + __ HCl (g)--> __NH4Cl (s)

Explanation / Answer

Balanced Equation is 1NH3 + 1HCl --> 1NH4Cl moles of NH3= 7/17 =0.411 moles of HCl=12/36.5=0.329 Therefore total reactsHCl with NH3 leaving (0.411-0.329) 0.082 moles of NH3 and 0.411 moles of NH4Cl. NH4Cl is solid hence NH3 left out is considered in number of moles Final Pressure= n*R*T/V=0.082*8.314*(25+273)/0.001=203160.9 Pa

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