A sample survey contacted an SRS of 663registered voters in Oregon shortly after

Question

A sample survey contacted an SRS of 663registered voters in Oregon shortly after an election and askedrespondents whether they had voted. Voter records show that 56% ofregistered voters had actually voted. We will see later that inthis situation the proportion of the sample who voted (call thisproportion ) has approximately the Normal distribution with mean = 0.56 and standard deviation = 0.019. (a) If the respondents answer truthfully,what is P(0.52 0.60)? This is the probability thatthe sample proportion estimates the population proportion 0.56within plus or minus 0.04. (b) In fact, 72% of the respondents saidthey had voted ( = 0.72). If respondents answer truthfully, what isP( 0.72)? This probability is so small that it is goodevidence that some people who did not vote claimed that they didvote. Thank you! A sample survey contacted an SRS of 663registered voters in Oregon shortly after an election and askedrespondents whether they had voted. Voter records show that 56% ofregistered voters had actually voted. We will see later that inthis situation the proportion of the sample who voted (call thisproportion ) has approximately the Normal distribution with mean = 0.56 and standard deviation = 0.019. (a) If the respondents answer truthfully,what is P(0.52 0.60)? This is the probability thatthe sample proportion estimates the population proportion 0.56within plus or minus 0.04. (b) In fact, 72% of the respondents saidthey had voted ( = 0.72). If respondents answer truthfully, what isP( 0.72)? This probability is so small that it is goodevidence that some people who did not vote claimed that they didvote.

Explanation / Answer

n= 663

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.