A conducting loop, shown in figure, is removed from the permanent magnet by pull
ID: 2245408 • Letter: A
Question
A conducting loop, shown in figure, is removed from the permanent magnet by pulling it vertically upward. a) What is the direction of induced current. ? b) Is a force required to remove the loo? Does the total amount of internal energy produced depend on time taken to remove it?
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6) Explain why the inductance of a coaxial cable is expected to increase when the radius of the outer conductor is increased, with the radius of the inner conductor remaining fixed.
Explanation / Answer
a. induced current i = induced emf /resistance
i = e/R
and direction is from right to left
b. force is required to remove it from the field as it is been acted by magnetic force
c. yes , energy depoends on time taken
d. inductance of a cooaxial tube of inner raidus a and outer raidus b is L = uo n A^2 /l
as is it dependent on radius a, it is inductnace L increases
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