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A conducting bar of length l moves to the right on two frictionless rails, as sh

ID: 1685023 • Letter: A

Question

A conducting bar of length l moves to the right on two frictionless rails, as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 2.90 T. Assume script l = 39 cm and R = 9.1 O.

http://www.webassign.net/sercp8/20-p-024.gif

(a) At what constant speed should the bar move to produce an 8.3 mA current in the resistor?
m/s

What is the direction of this induced current?


(b) At what rate is energy delivered to the resistor?
mJ/s

(c) Explain the origin of the energy being delivered to the resistor.

Explanation / Answer

A conducting bar of length l moves to the right on two frictionless rails, as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 2.90 T. Assume script l = 39 cm and R = 9.1 O.

http://www.webassign.net/sercp8/20-p-024.gif

(a) At what constant speed should the bar move to produce an 8.3 mA current in the resistor?
m/s

What is the direction of this induced current?


(b) At what rate is energy delivered to the resistor?
mJ/s

(c) Explain the origin of the energy being delivered to the resistor. Given that magnitude of magnetic feild B = 2.90 T length of rod l = 0.39 m resistance R = 9.10 O ------------------------------------------------------------- a)The formula for the induced emf is                  V = Blv                 (IR) = Blv So the speed of the bar is               v= (IR)/(Bl)                 = ((8.3 x10^-3A )( 9.10 O))/(( 2.90 T)(0.39 m))                = 0.066 m/s The direction of induced current is counter clock wise. b) The rate of energy delivered to the resistor is                 P = I^2 R                    = (8.3 x10^-3A )^2(9.10 O)                    = 0.000626899 W c) Origin of energy being delivered to resistor is from magnetic field
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