A circular coil enclosing an area of 101 cm2 is made of 200 turns of copper wire

Question

A circular coil enclosing an area of 101 cm2 is made of 200 turns of copper wire. The wire making up the coil has resistance of 5.0 , and the ends of the wire are connected to form a closed circuit. Initially, a 1.7 T uniform magnetic field points perpendicularly upward through the plane of the coil. The direction of the field then reverses so that the final magnetic field has a magnitude of 1.7 T and points downward through the coil. If the time required for the field to reverse directions is 0.14 s, what average current flows through the coil during that time?

Explanation / Answer

Faraday's Law: E = N d (BA) / dt E = ( 200 ) ( 2*1.7 T ) ( 101 cm^2 ) ( 1 m / 101 cm )^2 / .14 s E = 48 V so I = E / R = 48 V / 5 Ohms = 9.6 Amperes.

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