A square loop is rotating around it\'s vertical axis in a magnetic field of stre

Question

A square loop is rotating around it's vertical axis in a magnetic field of strength B = 0.06 T as shown in View A. The angular frequency of rotation is w = 50 rad/s and the loop has a resistance of R = 5 W. The length of one side of the square loop is W = 0.05 m. At the instant of time when the normal to the loop makes an angle of q = 30? with respect to the B field, as shown in View B where 'N' represents the normal, calculate the current flowing in the loop. Note: View A would be the side view if q = 90? or 270?. I = _________________ A

Explanation / Answer

v=r
v = W/2
=0.05/2x50

=1.25 m rad./s

e = 2BWvsin 30°

=2x0.06x0.05x1.25sin30

I=e/R

=0.00075 A

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