Light is incident along the normal to face of a glass prism of refractive index

Question

Light is incident along the normal to face of a glass prism of refractive index 1.58, as shown in the figure (Figure 1) .

answer 50.7 degrees

AC if the prism is immersed in water. alpha can have without any light refracted out of the prism at faceACif the prism is immersed in air. answer 50.7 degrees Part B:Find the largest value the anglecan have without any light refracted out of the prism at face Light is incident along the normal to face of a glass prism of refractive index 1.58, as shown in the figure (Figure 1) . Part a:Find the largest value the angle

Explanation / Answer

critical angle = arcsin (n2/n1) critical angle = 90-alpha parta : critical angle = arcsin (1/1.58) = 39.264 so alpha = 50.736 degrees partB : critical angle = arcsin (water refractive index / 1.58) = arcsin (1.33/1.58) = arcsin (0.842) so critical angle = 57.35 degrees so alpha = 90-57.35 = 32.65 degrees

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.