Light from an incandescent source transmits through a polarizer whose transmissi

Question

Light from an incandescent source transmits through a polarizer whose transmission axis makes an angle of 35.0degree with respect to the vertical; i. e., the 35.0 - degree mark on the polarizer lines up with the index mark on the component carrier. The light intensity after passing through the polarizer is 75.3 lux. At what angle would you need to set a second polarizer in order to have no light transmitted through the second polarizer? At what angle would you need to set the second polarizer to obtain a light intensity of 26.4 lux? Assume the polarizers are ideal. Please show detailed calculations.

Explanation / Answer

A) for no light is to be transmitted, the second polarizer must be placed 90 degrees with respect to the axis of the first polarizer.

or 90 + 35 = 125 degrees with vertical.

B) let theta is the angle made by second polarizer axis with first polarizer axis.

use, I = Io*cos^2(theta)

cos(theta) = sqrt(I/Io)

cos(theta) = sqrt(26.4/75.3)

theta = cos^-1(0.592)

= 53.7 degrees with respect to first polarizer or 88.7 degrees with respect to vertical.

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