Two blocks are sliding along a frictionless track. Block A (mass 4.75 kg) is mov

Question

Two blocks are sliding along a frictionless track. Block A (mass 4.75 kg) is moving to the right at 2.10 m/s. Block B (mass 5.70 kg) is moving to the left at 2.52 m/s. Assume the system to be both Block A and Block B. 1) What is the total momentum of the system before the collision? Is it to the left or the right? 2) What is the total momentum of the system after the collision? Is it to the left or the right? 3) The two blocks stick together and move off together. What is the magnitude and direction of the velocity of the blocks after the collision? Is it to the left or the right?

Explanation / Answer

a) 4.38

b ) left

c) momentum is conserved so it will be 4.38

d) 4.38 = 4.75*va + 5.7*vb

4.75*2.1^2 + 5.7*2.52^2 = 4.75va^2 + 5.7vb^2

from here get va and vb

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.