Two blocks are free to slide along the frictionless wooden track shown below. Th

Question

Two blocks are free to slide along the frictionless wooden track shown below. The block of mass m1 = 5.02 kg is released from the position shown, at height h = 5.00 m above the flat part of the track. Protruding from its front end is the north pole of a strong magnet, which repels the north pole of an identical magnet embedded in the back end of the block of mass m2 = 9.90 kg, initially at rest. The two blocks never touch. Calculate the maximum height to which m1 rises after the elastic collision.

height=_____m

Explanation / Answer

Here ,

at the bottom of the ramp

speed of block m1 before collision is u1

u1 = sqrt(2 * g * h )

u1 = 9.9 m/s

let the final speed of m1 and m2 is v1 and v2 after the collision

Using conservation of momentum

5.02 * v1 + 9.9 * v2 = 9.9 * 5.02 ------(1)

as the collision is elastic

v2 - v1 = 9.9 -----(2)

solving for v1 and v2

v1 = -3.23 m/s

v2 = 6.66 m/s

maximum height for m1 = v1^2/(2 * g)

maximum height for m1 = 3.23^2/(2 * 9.8)

maximum height for m1 = 0.532 m

the maximum height to which m1 rises after the elastic collision is 0.532 m

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