Figure P30.23 is a cross-sectional view of a coaxial cable. The center conductor

Question

Figure P30.23 is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, which is surrounded by an outer conductor, which is surrounded by another rubber layer. In a particular application, the current in the inner conductor is I11.18 A out of the monitor, and the current in the outer conductor is 12-3.20 A into the monitor Determine the magnitude and direction of the magnetic field at point a. AUT Director-.. ? Determine the magnitude and direction of the magnetic field at point b. AUT Directon ? ?. xi Figure P30.23

Explanation / Answer

First Part -

Here at the point a, the distance is r = 1 mm = 0.001 m.

At the same point...

B = µI1 / 2?r = ((4? x 10^-7 Tm/A) x 1.18 A) / (2? x 0.001 m)

= 2.36 x 10^-4 T

And its direction is upwards (towards the top).

Second Part -

At point b, the distance is R = 3 mm = 0.003 m.

At the same point -

B = µI2 / 2?R = ((4? x 10^-7 Tm/A) x 3.20 A) / (2? x 0.003 m)

= 2.13 x 10^-4 T

And its direction is downwards (towards the bottom).

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