Figure 8.2 A block of mass m = 2 kg has a speed V and is behind a block of mass

Question

Figure 8.2 A block of mass m = 2 kg has a speed V and is behind a block of mass M = 44 kg that has a speed of 0.5 m/s. The surface is frictionless. The blocks collide and couple. After the collision, the blocks have a common speed of 0.9 m/s. In Fig. 8.2, the impulse on the 2-kg block due to the collision is closest to: Figure 8.2 A block of mass m = 2 kg has a speed V and is behind a block of mass M = 44 kg that has a speed of 0.5 m/s. The surface is frictionless. The blocks collide and couple. After the collision, the blocks have a common speed of 0.9 m/s. In Fig. 8.2, the impulse on the 2-kg block due to the collision is closest to: 40 31 0.80 18 22

Explanation / Answer

impulse = m*(v2- v1)

= 2* (0.9-9.7)

= -17.6 Kg m/s

therefore closest to 18.

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