A lighted candle is placed d = 33 cm in front of a converging lens of focal leng

Question

A lighted candle is placed d = 33 cm in front of a converging lens of focal length f1 = 14 cm, which in turn is 55 cm in front of another converging lens of focal length f2 = 12 cm.

A lighted candle is placed d 33 cm in front of a converging lens of focal length f1-14 cm, which in turn is 55 cm in front of another converging lens of focal length f2 12 cm. 12cm 55 cm Calculate the position and relative size of the final image position magnification cm beyond the second lens x size of the real object

Explanation / Answer

d = 33 cm

f1 = 14 cm

f2 = 12 cm

Now

1/s1 + 1/s1’ = 1/f1 ======> 1/33 + 1/s1’ = 1/14 =====> s1’ = 24.3 cm

m1 = -s1’/s1 = -24.3/33 = -0.736 (image inverted)

And

1/s2 + 1/s2’ = 1/f2 =======> 1/30.7 + 1/s2’ = 1/12 =====> s2’ = 19.7 cm from 2nd lens

M2 = -s2’/s2 = -19.7/30.7 = -0.642 (inverts first image)

Total magnification = mT = m1*m2 = 0.473

So final image will be real and erect since mT > 0.

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