A hydrogen atom in its ground state absorbs a phonto of wavelenghtof 94.97 nm. I

Question

A hydrogen atom in its ground state absorbs a phonto of wavelenghtof 94.97 nm. It then emits a photon of wavlenght of 1282 nm.

A. to which level was the elctron excited when it absorbed 94.97 nmphonton?
B. Which level was the elctron in after it emitted 1282 nmphonton.

Explanation / Answer

   For a hydrogen atom,    En = -2.18*10-18/n2 J    => E = En - E1 = hc/, ie. theenergy gained by the atom through radiation causing its electron toget excited. => 2.18*10-18* [ 1 - 1/n2] =6.626*10-34*3*108/94.97*10-9 J => n = 5 B. On emitting 1282 nm radiation,     En - E5 = -hc/    => 2.18*10-18* [ 1/25 - 1/n2]=-6.626*10-34*3*108/1282*10-9 J    => n = 3.

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