A hydrated form of copper sulfate (CuSO4·x H2O) is heated to drive off all the w

Question

A hydrated form of copper sulfate (CuSO4·x H2O) is heated to drive off all the water. If we start with 7.48 g of hydrated salt and have 4.18 g of anhydrous CuSO4 after heating, find the number of water molecules associated with each CuSO4 formula unit.

Question 4 of 13 General Chemistry 4th Edition University Science Books presented by Sapling Learning Map A hydrated form of copper sulfate (CuSO4" x H20) is heated to drive off all the water. If we start with 7.48 g of hydrated salt and have 4.18 g of anhydrous CuSO4 after heating, find the number of water molecules associated with each CuSO4 formula unit. Number Previous Give Up & View Solution O Check Answer Next Exit Hint

Explanation / Answer

mass of H2O = mass of hydrated salt - mass of anhydrous salt

mass of H2O = 7.48 g - 4.18 g

mass of H2O = 3.3 g

Molar mass of H2O = 2*MM(H) + 1*MM(O)

= 2*1.008 + 1*16.0

= 18.016 g/mol

mass(H2O)= 3.3 g

we have below equation to be used:

number of mol of H2O,

n = mass of H2O/molar mass of H2O

=(3.3 g)/(18.016 g/mol)

= 0.1832 mol

Molar mass of CuSO4 = 1*MM(Cu) + 1*MM(S) + 4*MM(O)

= 1*63.55 + 1*32.07 + 4*16.0

= 159.62 g/mol

mass(CuSO4)= 4.18 g

we have below equation to be used:

number of mol of CuSO4,

n = mass of CuSO4/molar mass of CuSO4

=(4.18 g)/(159.62 g/mol)

= 2.619*10^-2 mol

we have below equation to be used:

X = mol (H2O)/mol (CuSO4)

X = 0.1832 / 2.619*10^-2

X = 7

Feel free to comment below if you have any doubts or if this answer do not work

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