A hydrogen atom in the n =5 state decays tothe n =3 state. What isthe wavelength

Question

A hydrogen atom in the n=5 state decays tothe n=3 state. What isthe wavelength of the photon that the hydrogen atomemits?

nm

While in the first excited state, a hydrogen atom is illuminated byvarious wavelengths of light. What happens to the hydrogen atomwhen illuminated by each wavelength?
434.2 nm?   -pick one-stays in n=2 statejumps to n=3 statejumps to n=4 statejumps to n=5 statejumps to n=6 stateis ionized

572.4 nm?   -pick one-stays in n=2 statejumps to n=3 statejumps to n=4 statejumps to n=5 statejumps to n=6 stateis ionized

322.6 nm?   -pick one-stays in n=2 statejumps to n=3 statejumps to n=4 statejumps to n=5 statejumps to n=6 stateis ionized
434.2 nm?   -pick one-stays in n=2 statejumps to n=3 statejumps to n=4 statejumps to n=5 statejumps to n=6 stateis ionized

572.4 nm?   -pick one-stays in n=2 statejumps to n=3 statejumps to n=4 statejumps to n=5 statejumps to n=6 stateis ionized

322.6 nm?   -pick one-stays in n=2 statejumps to n=3 statejumps to n=4 statejumps to n=5 statejumps to n=6 stateis ionized

Explanation / Answer

According into Redberg equation ( 1/ lamda) = R [ ( 1/ n^ 2 )– ( 1/ n’ ^ 2 )]

Where R = rydberg cosnatnt = 10.96 * 10 ^ 6 m^ -1

           n= 3

           n '= 5

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