A spring of spring constant128N/m iscompressed a distance of 2.0m from itsequili

Question

A spring of spring constant128N/m iscompressed a distance of 2.0m from itsequilibrium

(unstretched, uncompressed)position, and used to project a ball of mass 4.0 kg directlyupwards.

Neglect airresistance.

1. [5 pts] What is the potentialenergy of the spring in its compressed position?

2. [8 pts] To what maximumheight above its initial(compressed) position does the ball

reach? (At this height, the ballis no longer in contact with the spring.)

3. [12 pts] Earlier, just whenthe spring returned to its equilibrium position, as theball

was moving upwards, how fast was the ballmoving?

Explanation / Answer

    we are given with     k = 128 N / m     x = 2.0 m     m = 4.0 kg (a)     PE = (1 / 2) k x2 (b) and (c)     PE = KE          = (1 / 2) mv2     v = ........ m / s     v = (2 g h)     h = ......... m

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