A solid conducting sphere with radius R = 0.590 m carries a net charge of +0.350

Question

A solid conducting sphere with radius R = 0.590 m carries a net charge of +0.350 nC. Electric field: Find the electric field: at a point 0.100 m outside the surface of the sphere. E vector N/C r^at a point inside the sphere, 0.100 m below the surface. E vector == N/C Also, sketch Er vs. r from r=0 to infinity. On your graph, mark off where r=R occurs. Inside the sphere (r R), graph's shape is: Voltage: Setting V=0 at r=infinity, find the voltage at the following locations: V(r = R) = V V(r = 0 cm) = V Also, sketch V vs. r from r=0 to infinity. On your graph, mark off where r=R occurs. Inside the sphere (r R), graph's shape is:

Explanation / Answer

b)

at V (r = R).

V = k Q/R = (9 x 109) (0.35 x 10-9)/(0.590) = 5.34 volts

at V(r =0)

V(r=R) = V(r=0) = 5.34 volts

since inside electric field is 0 , hence the potential difference remains same

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