A solid block is attached to a spring scale. The reading on the scale when the b

Question

A solid block is attached to a spring scale. The reading on the scale when the block is completely immersed in water is 25.0 N , and the reading when it is completely immersed in alcohol of density 806 kg/m3 is 25.5 N .

Part A

What is the block's volume?

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Part B

What is the block's density?

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A solid block is attached to a spring scale. The reading on the scale when the block is completely immersed in water is 25.0 N , and the reading when it is completely immersed in alcohol of density 806 kg/m3 is 25.5 N .

Part A

What is the block's volume?

V =   m3  

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Part B

What is the block's density?

block =   kg/m3  

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Explanation / Answer

supopse volume of block is V and density is rho.

when completely submerged in fluid,

N = m g - Fb

where Fb = buoyant force = V rho_fluid g

When in water:

25 = V rho g - 1000 V g

V rho g = 25 + 1000 V g .... (i)

When in alocohol.

25.5 = V rho g - 806 V g

V rho g = 25.5 + 806 V g ..... (ii)

hence 25 + 1000 V g = 25.5 + 806 V g

V = 2.63 x 10^-4 m^3 ..........Ans(A)

(B) putting in (i),

V rho g = 25 + 1000 V g

(2.63 x 10^-4) rho (9.8) = 25 + (1000 x 2.63 x 10^-4)(9.8)

rho = 10700 kg / m^3

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