A projectile is launched into the air ground level heading east. The projectile

Question

A projectile is launched into the air ground level heading east. The projectile is launched at an angle of 30 degree with an initial velocity of 20m/s. The wind is blowing the projectile in the north direction, with a constant acceleration of 2m/s^2. Assuming gravity is 9.8m/s^2, where does the projectile land in relation to its starting position?( use vectors to solve the problem.) A projectile is launched into the air ground level heading east. The projectile is launched at an angle of 30 degree with an initial velocity of 20m/s. The wind is blowing the projectile in the north direction, with a constant acceleration of 2m/s^2. Assuming gravity is 9.8m/s^2, where does the projectile land in relation to its starting position?( use vectors to solve the problem.)

Explanation / Answer

range of projectile = v^2 * sin(2 * theta) / g

range of projectile = 20^2 * sin(2 * 30) / 9.8

range of projectile = 35.3479 m

time of flight = 2 * v * sin(theta) / g

time of flight = 2 * 20 * sin(30) / 9.8

time of flight = 2.04 sec

by second equation of motion

s = ut + 0.5 * at^2

s = 0 + 0.5 * 2 * 2.04^2

s = 4.16 m

projectile will land at

x = 35.3479i + 4.16j

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