A projectile is fired with an initial speed of 29.0 m/s at an angle of 65.0 abov

Question

A projectile is fired with an initial speed of 29.0 m/s at an angle of 65.0 above the horizontal. The object hits the ground 9.50 s later.

A) How much higher or lower is the launch point relative to the point where the projectile hits the ground?

Express a launch point that is lower than the point where the projectile hits the ground as a negative number.

B) To what maximum height above the launch point does the projectile rise?

C) What is the magnitude of the projectile's velocity at the instant it hits the ground?

D) What is the direction (below +x) of the projectile's velocity at the instant it hits the ground?

Express your answer using two significant figures.

Explanation / Answer

given that initial speed of partical

u=29m/s

Q=65=angle of projectile

T=time of flight=9.5 s

(B) we know that

maximum hight for flight

Hmax =u2sin2Q/2g g=10m/s2

=29 x29 sin265 /20 =34.7681  m

(A)

How much higher or lower is the launch point relative to the point where the projectile hits the ground? it means we have to find the range of the partical

R=u2sin2Q / g

=29x29sin130 /10

=-78.2219 m

mean78.2219 m down from projectile

(C)we know that the horizontal factor of velcity is constant

so velocity in x direction will u cosQ=29cos65=-16.31116m/s

here -ive sign shows the direction

vertical component of velocity at touching the ground will equales to the gT/2

because at max hight velocity will be zero it takes T/2 time for touch the ground

so for motion in y direction u=o a=g and t=T/2

by using V=U+at

V=gT/2=75.5m/s downword

they both velocity are at perpandiculer so resultant of them will be

by pythegorean theorm resultantV

V=sqrt[(16.3116)2+(75.5)2]

V=77.241 m/s

(D)

because they both are perpandiculer so direction will be

tanQ =qsinQ/p+qcosQ

let vertical component is q

so tanQ=75,5sin90/(16.3116+75.5cos90)

tanQ=75.5/16.3116=4.6286

Q=1.35801

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.