A projectile fired from the point? (0,0) at an angle to the positive? x-axis has

Question

A projectile fired from the point? (0,0) at an angle to the positive? x-axis has a trajectory given by y=Cx - (1 + C)^2 (g /2 ) (x / v )^2

894

x=horizontal

y=height

v=initial

g=acceleration

gravity=9.81 m/sec2

C>0

?(a) If the round must clear a hill

219

meters high at a distance of

1878

meters in front of the? howitzer, what C values are permitted in the trajectory? equation?

Right answer: (0.128,86.636)??

?(Type your answer in interval notation. Round the final answer to the nearest thousandth as needed. Round all intermediate values to five decimal places as? needed.)

?(b) If the goal in part ?(a) is to hit a target on the ground

72

kilometers? away, is it possible to do? so? If? so, for what values of? C? If? not, what is the maximum distance the round will? travel?

?(Use a comma to separate answers as needed. Round the final answer to the nearest thousandth as needed. Round all intermediate values to five decimal places as? needed.)

Note: Hey there! I was able to solve part A after multiple attempts. Now, I've done part B one time and it turned incorrect with the answers (0.602, 1.661). I've got two more tries left. Help me with part B, please? Thanks!

Here's the problem incase pasting it doesn't make sense:

A projectile fired from the point? (0,0) at an angle to the positive? x-axis has a trajectory given by y=Cx - (1 + C)^2 (g /2 ) (x / v )^2

A howitzer fires an artillery round with a velocity of

894

?m/sec.

x=horizontal

distance in meters

y=height

in meters

v=initial

velocity in meters per second

g=acceleration

due to ?????

gravity=9.81 m/sec2

C>0

is a constant determined by the angle of elevation.?? C Secure https/www.mathxl.com/Student/Playerh homeworkdd 482878605&questionld-6;&flushed-faise;&cld-50077798back; DoAssig Math 162 3182 Bianca Blanco&1 5/14/18 9:58 PM Homework: 3.5 Score: 0.5 of 1 pt HIV Score: 91.67% 5.5 of 6 pts 3.5.37 A projectile fired from the point (0.0) at an angle to the positive x-axis has a trajectory given by honzontal distance in meters -height in meters intial velocity in meters per second acceleration due to gravity-9.81 m/sec2 >0 is a constant determined by the angle of elevation A howitzer fires an artillery round with a velocity of 894 mlsec. ? the sound must clear a hil 219 meters high at a dstance of 1878 meters front of the howtzer, what C values are permitted the trajectory equation? 0128.86 636) (Type your answer in intervail notation Round the final answer to the nearest thousandth as needed Round all intermediate values to five decimal places as needed) (bj itf the goal in part (a) is to hit a target on the ground 72 kilometers away, is it possible to do so? Ii so, for what values of C? 1f not, what is the maximum distance the round vall travel? 0.502 1 Use a comma to separate answers as needed Round the final answer to the nearest thousandth as needed Round all intermediate values to five decimal places as needed ) answer in the answer box and then click Check Answer Clear Al

Explanation / Answer

y = Cx - (1 + C)^2 * (g/2) * (x/v)^2

219 = C(1878) - (1 + c)^2 * (9.81/2) * (1878/894)^2

219 = 1878C - 21.644878383856583(1 + C)^2

C = 0.128 , 86.636

-------------------------------------------------------------

Now, we have x = 72000 and y = 0 instead

0= C(72000) - (1 + c)^2 * (9.81/2) * (72000/894)^2

0 = 72000C - 31814.7831178775730823(1 + C)^2

C = undefined

No solutions exist for C

The max distance travelled would be :

0 = xC - (1+C)^2 * (9.81/2) * (x/894)^2

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