A sign (mass 2400 kg ) hangs from the end of a vertical steel girder with a cros

Question

A sign (mass 2400 kg ) hangs from the end of a vertical steel girder with a cross-sectional area of0.017 m2 . Ignore the mass of the girder itself. The elastic modulus for steel is 2.0×1011N/m2.

Part A

What is the stress within the girder?

Express your answer to two significant figures and include the appropriate units.

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Part B

What is the strain on the girder?

Express your answer to two significant figures.

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Part C

If the girder is 5.60 m long, how much is it lengthened?

Express your answer to two significant figures and include the appropriate units.

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Explanation / Answer

Assuming Modulus of Elasticity for Steel = 2 * 10^11N / m^2


(a) What is the stress within the girder?

stress = Force / cross -sectional area = (2400*9.81) / 0.017 = 1384941.17 N / m^2.............ans


(b) What is the strain on the girder?
Strain = Stress / Young's modulus = (1384941.17) / ( 2* 10^11) = 6.9247* 10^-6...............ans

c) If the girder is 5.6 m long, how much is it lengthened?
elongation = strain x length = 6.9247* 10^-6 * 5.6= 3.877*10^-5 m

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