For the real battery shown in the figure, calculate the power dissipated by a re

Question

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 0.20 ? .

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 0.45 ? .

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 1.0 ? .

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 2.5 ? . (Your results should suggest that maximum power dissipation is achieved when the external resistance R equals the internal resistance. This is true in general.)

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 3.0 ? .

Explanation / Answer

total resistance = internal + external resistance

a) i = 1.5/(1+2) = 0.5A

Power dissipated = i^2 * R = 0.5*0.5*2 = 0.5W

b) i = 1.5/(1+0.45) = 1.034A

Power = 1.034*1.034*0.45 = 0.48W

c) i = 1.5/2 = 0.75A

Power = 0.75*0.75*1 = 0.5625W

d) i = 1.5/(3.5) = 0.428A

Power = 0.458W

e) i = 1.5/4 = 0.375A

Power = 0.375*0.375*3= 0.421W

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