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For the reaction, 2COF_2(g) CO_2(g) + CF_4(g) K_c = 2.00 at a particular tempera

ID: 1072951 • Letter: F

Question

For the reaction, 2COF_2(g) CO_2(g) + CF_4(g) K_c = 2.00 at a particular temperature. A reaction mixture at this temperature initially contains all three gases in equal concentrations. Which is true of this reaction mixture? Q K; the reaction proceeds toward the reactants The reaction A rightarrow products obeys second order kinetics. What is the molar concentration of A remaining after 2.00 minutes if the reaction has a rate constant of 0.0482 M^-1 s^-1 and the initial concentration of A is 0.379 M. 0.0655 M 0.119 M 0.366 M 8.42 M Determine the reaction order with respect to [A] for the reaction A + B + C rightarrow products. 0 1 1.5 2

Explanation / Answer

Q32

Q = [CO2][CF4]/[COF2]^2

assume "x" is the equal concentration value

so

[CO2]= x

[CF4]= x

[COF2] = x

then

Q = (x*x)/(x^2) = 1

since Q < K

expect reactants to be favoured, so choose B

Q33

if 2nd order, then

1/A = 1/A0 + kt is true

t = 2, k = 0.0482 and A0 = 0.379

substitute data

1/A = 1/(0.379) + 0.0482*2

1/A = 2.7349

A = 2.7349^-1 = 0.365644, choose C

Q34.

for A:

choose point 3 and 4

Rate 3 / Rate 4 = (A3/A4)^a * (B3/B4)^b * (C3/C4)^c

then

(2.4*10^4)/(2.4*10^4) = (0.2/0.1)^a

A = 0 order, since change in A will not affec tthe rate

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