For the reaction below, the instantaneous initial rate of reaction is 3.87 X 10^
ID: 940305 • Letter: F
Question
For the reaction below, the instantaneous initial rate of reaction is 3.87 X 10^-3 Ms^-1 when [A] = 6.10 times 10^-3 M and [B] 4.25 times 10^-4 M. What is the rate constant for this reaction if the rate law is stoichiometric with the equation? You must include proper units for the constant! 2 A + 3 B right arrow C Classify each reaction as unimolecular, bimolecular, or termolecular. 2 NO + Br_2 right arrow 2 NOBr CH_3NC right arrow CH_3CN CH_3Br + OH^1-right arrow CH_3OH + Br^1- The equation for the combustion of butane is shown below. Why is it unlikely that this reaction occurs in a single step? Your answer must be specific. 2 C_4.|H_10(g) + 13 O_2(g) right arrow 8 CO_2(g) + 10 H_2O(g)Explanation / Answer
Answer – 8) We are given, [A] = 6.10*10-3 M, [B] = 4.25*10-4 M ,
Reaction – 2A + 3 B -----> C , Rate = 3.87*10-3 M.s-1
The rate law is stoichiometric with equation –
So, rate = k[A]2[B]3
3.87*10-3 M.s-1 = k *(6.10*10-3 M)2 (4.25*10-4 M)3
3.87*10-3 M.s-1 = k * 2.86*10-15M5
So, k = 3.87*10-3 M.s-1 / 2.86*10-15 M5
= 1.35*1012 M-4.s-1
9) In this there is given the reaction and nee to determine the it is unimolecular or bimolecular or termolecular
We know the molecularity of reaction is depending on the moles of reactant take part in the rate determining step of reaction. The unimolecular reaction means in the transition state there is only one reactant molecule, for the biomolecular reaction there are 2 molecules in the transition state and for the termolecular improbability of three molecular entities simultaneously collided, so they are rear.
A) In this one there are total 3 molecules in the reactant, so it is termolecular reaction.
B) In this one there is only on molecules in the reactant, so it is unimolecular reaction.
C) In this one there are two molecules in the reactant, so it is bimolecular reaction.
10) In the butane combustion reaction there are 2 molecules are reacting simultaneously, so it molecularity and rate law is more than first order, so it is is unlike to complete in a single step reaction.
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