For the real battery shown in the figure, calculate the power dissipated by a re

Question

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 0.65 ? .

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 1.0 ? .

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 2.5 ? . (Your results should suggest that maximum power dissipation is achieved when the external resistance R equals the internal resistance. This is true in general.)

For the real battery shown in the figure, calculate the power dissipated by a resistor R connected to the battery when R = 4.5 ? .

Explanation / Answer

current i = emf/r+R

1) i = 1.5/1+0.15 = 1.5/1.15 = 1.304 amp

power = i^2*R = 0.255 W

2) I = 1.5/1+0.65 = 0.909 A

POWER = I^2R = 0.537 W

3) I = 1.5/1+1 = 0.75 A

POWER = 0.75^2*1 = 0.5625 A

4) I = 1.5/1+2.5 = 0.429 A

POWER = 0.429^2*2.5 = 0.459 W

5) I = 1.5/1+4.5 = 0.273 A

POWER = 0.273^2*4.5 = 0.335 W

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