For the reaction whose reactants and products are: reactants: C (graphite) H 2 O

Question

For the reaction whose reactants and products are:

reactants: C (graphite) H2O (l)

products: CH3COOH(l)   The standard enthalpy change is 8.7 (J/mol-K) Calculate Suniverse in J/mol-K for theprocess at 298.15K. Balance all chemical reactions using the loweset ratio ofwhole numbers. For the reaction whose reactants and products are:

reactants: C (graphite) H2O (l)

products: CH3COOH(l)   The standard enthalpy change is 8.7 (J/mol-K) Calculate Suniverse in J/mol-K for theprocess at 298.15K. Balance all chemical reactions using the loweset ratio ofwhole numbers.

Explanation / Answer

   The givn data is     The standard enthalpy change =8.7L/mol-k     The balanced chemical reaction is     2C(graphite)+2H2O(l)----> CH3COOH(l)      For the Above reaction    S = nS0(products)- nS0 (reactants)          = (1mol*159.8 J/kmol -(1mol*5740  J/kmol +2mol 69.91J/kmol )          = 159.8J/k-145.56 J/k           = 14.28J/K     SUni=(-H/T)+S               =-8.7 J/298.15K+14.28                =- 14.25J/k

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.