For the reaction whose reactants and products are: reactants: C (graphite) H 2 O

Question

For the reaction whose reactants and products are:

reactants: C (graphite) H2O (l)

products: CH3COOH(l)   The standard enthalpy change is 8.7 (J/mol-K) Calculate Suniverse in J/mol-K for theprocess at 298.15K. Balance all chemical reactions using the loweset ratio ofwhole numbers. For the reaction whose reactants and products are:

reactants: C (graphite) H2O (l)

products: CH3COOH(l)   The standard enthalpy change is 8.7 (J/mol-K) Calculate Suniverse in J/mol-K for theprocess at 298.15K. Balance all chemical reactions using the loweset ratio ofwhole numbers.

Explanation / Answer

The reaction is C(graphite) + 2H2O(l) .............>CH3COOH (l) Given : H = 8.7J/mol.K and T = 298.15K For the above reaction S = nS0 (products) -nS0 (reactants)      = (1mol* 159.8J/K.mol) -(1mol*5.740J/K.mol + 2mol*69.91J/K.mol)      = 159.8J/K -145.56J/K      = 14.28J/K We know that, Suni = (-H / T) +S                              (-H / T = S surr) and S is Ssys                                   = -8.7J / 298.15K + 14.28J/K                                   = 14.25J/K

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