For the reaction whose reactants and products are: reactants: C (graphite) H 2 O

Question

For the reaction whose reactants and products are:

reactants: C (graphite) H2O (l)

products: CH3COOH(l)   

calculate the standard entropy change So(J/mol-K). The answer depends on how you balance the equation. Forthis question balance the equation using the smallest ratio ofWHOLE numbers.

Explanation / Answer

2C (graphite) + 2H2O (l) ---->CH3COOH(l) S°rxn = S°products -S°reactantsS° C(graphite) = 5.740J/mol-K S° H2O = 69.96 J/mol-K S° CH3COOH = 160 J/mol*K So, S°rxn = (1 mol * 160 J/mol-K) - [(2 mol *5.740 J/mol-K) + (2 mol * 69.91 J/mol-K)] S°rxn = 160 J/mol-K - (11.48 J/mol-K + 139.82J/mol-K) S°rxn = 8.7 J/mol*K

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