A very thin 25.0cm copper bar is aligned horizontally along the east-west direct

Question

A very thin 25.0cm copper bar is aligned horizontally along the east-west direction.

A) If it moves horizontally from south to north at 12.0 m/s in a vertically upward magnetic field of 1.24 T, what potential difference is induced across its ends?
Vab = __________ V

B) If it moves horizontally from south to north at 12. m/s in a vertically upward magnetic field of 1.24 T, which end (east or west) is at a higher potential?

C) What would be the potential difference if the bar moved from east to west instead?
Vab' = __________ V

Explanation / Answer

a)

potential difference = Blv = 1.24*.25*12 = 3.72 V
b)

west

c)

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