A reaction A(aq) + B(aq) C(aq) has a standard free-energy change of -3.38 kJ/mol

Question

A reaction A(aq) + B(aq) C(aq) has a standard free-energy change of -3.38 kJ/mol at 25 degree C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? How would your answers above change if the reaction had a standard free-energy change of +3.38 kJ/mol? All concentrations would be higher. There would be more A and B but less C. There would be no change to the answers. All concentrations would be lower. There would be less A and B but more C.

Explanation / Answer

a=.15M b=.20M c=.35M

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